If $abc=13$ and$\left(a+\frac{1}{b}\right)\left (b+\frac{1}{c}\right)\left(c+\frac{ 1}{a}\right)=\left(1+\frac{1}{a}\ri ght)\left(1+\frac{1}{b}\right)\left (1+\frac{1}{c}\right),$find $a+b+c$.

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11