One endpoint of a line segment has coordinates represented by (x+2, 1/4y). The midpoint of the line segment is (6, -3). How are the coordinates of the other endpoint expressed in terms of x and y? (14-x, 3-1/4y)
(12-x, 6-1/4y)
(10-x, -1/4y)
(10-x, -6-1/4y)

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

inverse property is the answer

step-by-step explanation:

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)