Solve the system by substitution.
−7x−10y= 40
x=−2y

x= -20, y= 10

Step-by-step explanation:

Label the two equations:

-7x -10y= 40 (1)

x= -2y (2)

Substitute (2) into (1):

-7(-2y) -10y= 40

Expand:

14y -10y= 40

Simplify:

4y= 40

Divide both sides by 4:

y= 40 ÷4

y= 10

Substitute y= 10 into (2):

x= -2y

x= -2(10)

x= -20

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0