Find the gradient of a straight line with the points P(5,3) and Q(8,12)

Step-by-step explanation:

the formula is y2-y1/x2-x1

points (p,5 is x1 whiles 3 is y1)

point (Q,8 is x2 whiles 12 is y2

so 12-3/8-5

so 12-3 is 9 and 8-5 is 3

so the answer is 9/3

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)