Two small circles are drawn that touch each other, and both circles touch the large circle. 7 in. 7 in. Which is closest to the area of the shaded region? *the photo is much better*
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308 inches

Step-by-step explanation:

since the two radiuses of the small circles become the diameter of the big circle, you can substitute 14 into the equation A= pi r^2 to get A=pi(14)^2, which gets you 615 inches. But then you have to subtract the area of two of the small circles, which if you add them two up, you get 307.87 inches. Then, you subtract the area of the big circle with the two small circles to get 307.87, which is closest to 308 inches.

Area of shaded region = 307.88 inch ^2

= 308 inch^2

Step-by-step explanation:

Radius of smaller circle = 7 inch radius

Area of SC = π * 7^2

= 153.93804

= 153.93 inch^2

2 x 7 = 14   (for main radius as two circles touching each other inscribed

would translate as R = 2r.

Area of two circles = 2 * 153.93804 = 307.87608

= 307.88 inch^2

Area of whole large circle

Area LC  = π * 14^2

= 615.75216

Area of shaded region

Area of Sh Region = 615.75216 - 307.87608 =307.87608

= 307.88 inch ^2

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation: