According to Descartes's rule of sign, how many possible positive and negative roots are there for the equation 0= -4x6-3x5+2x2-4x+1?

There are Real Roots for the Equation

According to Descartes Rule of Sign, The maximum number of real roots a polynomial equation has is the number of times the sign of term changes from a higher power term to a lower power term.

In the given equation, , we can already see that from to we can see that the sign didn't change so there might be no real roots. From to , we can see that the signs change so we now know that there might be real root for equation. From to , the signs changed so there might be real roots. From to , it changed again so there might be real roots. There are no other term with lesser power to compare for so we are left with real roots.

correct answer:

a + bi

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.