determine the kinetic energy of a 1000-kg roller coaster car that is moving with a soeed if 20.0 m/s.

200000J/200KJ

Step-by-step explanation:

using k.e=1/2(mv2)

k.e=1×1000×20²/2

k.e=400000/2

k.e=200000J/200KJ

the answer is c)8

step-by-step explanaction:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204