3x+2>5x-8

Can some one help me with this problem

5 > x

Step-by-step explanation:

3x+2>5x-8 rewrite the inequality by exporting like terms to the same side

2+8 > 5x - 3x now add/subtract like terms

10 > 2x divide both sides by 2

5 > x

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

10000

step-by-step explanation: divide by 2,