PL HELP For the graph y = 1 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your answer with two or more sentences.

see explanation

Step-by-step explanation:

y = 1 is the equation of a horizontal line parallel to the x- axis.

Since it is parallel to the x- axis then its slope is zero.

A line perpendicular to it will therefore be a vertical line parallel to the y- axis.

The slope of the perpendicular line is undefined.

The slope of a parallel line is zero

The slope parallel to the line is zero. The slope perpendicular to the line is undefined since y=1 has a slope of zero.

Explanation:

For the equation y=1  you would rewrite it as y = 0x +1 and it would just be a straight line that is one up from the x-axis.

Also an easy way to find the slope of a line that is perpendicular is to remember that the slope is the opposite reciprocal, meaning you just flip the slope you have in the original equation so if its 3/1 flip it to 1/3

However, parallel lines are equal to the slope, so basically the slope stays the same.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

answer: (3,11) is your answer.