2x-3x²=5 in standard formation​

Step-by-step explanation:

1. Make the equation equal to zero

2x - 3x^2 = 5 = 0

2. Then apply simple algebra by subtracting -5 from +5

2x - 3x^2 = 5 = 0

                  -5

3. Now move the -5 to the left side of the equation

2x - 3x^2 -5 = 0

4. Now arrange the numbers into standard form (ax^2 + bx + c)

-3x^2 + 2x - 5

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a