Use the geometric definition of the cross product and the properties of the cross product to make the following calculation. ((j+ k) x j ) x k=

By definition of the cross product,

i × i = j × j = k × k = 0

i × j = k

j × k = i

k × i = j

Also, the cross product is anticommutative. That is, for any two vectors a and b, we have

a × b = - (b × a)

The cross product distributes over sums:

((j + k) × j) × k = ((j × j) + (k × j)) × k

The rest follows from the definition and property mentioned above:

((j + k) × j) × k = (0 + (k × j)) × k

((j + k) × j) × k = (k × j) × k

((j + k) × j) × k = (-(j × k)) × k

((j + k) × j) × k = (-i) × k

((j + k) × j) × k = -(i × k)

((j + k) × j) × k = k × i

((j + k) × j) × k = j

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°