Find the zero of the polynomial in each of the following cases (I) P(x) = x + 5
(II) P(x) = x - 5
(III) P(x) = 2x + 5​

(I) (-5) is a zero of P(x)

(II) 5 is a zero of P(x)

(III) (-5/2) is a zero of P(x)

Step-by-step explanation:

Here, P(x) = x + 5

To find the zeroes of P(x)

let P(x) = 0

∴ x + 5 = 0

∴ x = (-5)

Thus, (-5) is a zero of P(x)

Here, P(x) = x - 5

To find the zeroes of P(x)

let P(x) = 0

∴ x - 5 = 0

∴ x = 5

Thus, 5 is a zero of P(x)

Here, P(x) = 2x + 5

To find the zeroes of P(x)

let P(x) = 0

∴ 2x + 5 = 0

∴ 2x = -5

∴ x = (-5/2)

Thus, (-5/2) is a zero of P(x)

-TheUnknownScientist

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

what? ?

what type of question is thiss

step-by-step explanation: