3. If p = 2q^2 - 5 and q = 10 - 3r, find r when p equals 67​

r =

Step-by-step explanation:

When p = 67 , then

2q² - 5 = 67 ( add 5 to both sides )

2q² = 72 ( divide both sides by 2 )

q² = 36 ( take square root of both sides )

q = = 6

Then

6 = 10 - 3r  ( subtract 10 from both sides )

- 4 = - 3r ( divide both sides by - 3 )

= r , that is

r =

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!

omg what happend to your question? if you could edit this question i can

step-by-step explanation: