What is the equation in polnt-slope form of the line passing through (-2, 1) and (4, 13)? (1 point) O a
y-1=-2(x – 4)
Ob
y- 1 = 2(x + 2)
ос
y - 13 = -2(x + 2)
Od
y - 13 = 2(x + 4)

b

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m =

with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (4, 13)

m = = = = 2

Using the point (- 2, 1 )

y - 1 = 2(x - (- 2)) , that is

y - 1 = 2(x + 2) → b

Using the point (4, 13)

y - 13 = 2(x - 4) ← not one of the options

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w