A ladder 13 m long when set against the wall of house just reaches a window at a height of 12 m from the ground. How far is the lower end of the ladder from the base of the wall?

Let the ladder be AB=13m

Let the vertical height reached be AC=12m

Let the distance between the foot of the ladder and wall be BC= x meters

By Pythagoras Theorem,

(AB)^2=(AC)^2+(BC)^2

(13)^2=(12)^2+(x)^2

x^2=169-144

x^2=25

x = 5 meters

Therefore,the foot of the ladder is 5 m away from the wall.

Step-by-step explanation:

Hope this helps!!!

:))

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

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step-by-step explanation: