PLEASE HURRY 50 POINTS!! What is the solution set for 3(1−r)<−2r−4?

r>7

r<1

r>−7

r<−1

the solution set is r>7

step by step:

Subtract 3 from both sides

3−3r−3<−2r−4−3

Simplify

−3r<−2r−7

Add 2r to both sides

−3r+2r<−2r−7+2r

Simplify

−r<−7

Multiply both sides by −1 (reverse the inequality)

(−r)(−1)>(−7)(−1)

Simplify

r>7

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1