Can anyone help? Will give + 22 pts . Question : A woman has a total of 9,000 to invest. She invest parts of the money in an account that pays 8% per year and the rest in an Account that pays 10% per year. if the interest earned in the first year is $800, how much did she invest in each account?

She invested $___ at 8% and $___ at 10%

0.08*x   + 0.09*(9000-x) = 750    dollars

0.08x + 810 - 0.09x = 750

-0.01x = 750 - 810 = -60  >  x = %28-60%29%2F%28-0.01%29 = 6000.

Answer.  $6000 was invested at 8%.  The rest   9000-6000 = 3000 dollars were invested at 9%.

Check.   0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars.   ! Correct !

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$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

ou would have 12 of each