The length of a rectangle is 1 units more than the width. The area of the redangle is 56 units. What is the width, in units, of the rectangle?

27.5 is the width

Step-by-step explanation:

First set up an equation.

(w+1)+w=56

This simplifies to...

2w+1=56

Now you need to isolate the w. Subtract 1 on both sides.

2w=55

Now divide 2 on both sides.

55/2 = 27.5

w=27.5

Hopefully you understand! Please give this "brainliest"! Thank you and have a great day! :)

The width is 7 units.

Step-by-step explanation:

What we know:

- Area of the rectangle is 56

- The length of a rectangle is 1 unit more than the width

I will be using the variable w to represent the width.

Let's write it out:

Length = w + 1

Width = w

We know that the area is length x width

So the equation is (w + 1) x w = 56

Let's simplify this equation!

w^2 + w = 56

Now we need to find the solutions of this equation and see which one works.

Rewrite the eqaution:

w^2 + w - 56 = 0

Factor, find two factors of -56 whose sum equals the coefficient of the middle term (w):

-7, 8

Rewrite:

w^2 - 7w + 8w - 56 = 0

This part is a little tricky for me to explain, I apologize in advance for any confusion, but you want to do a little something like this:

(w+8) x (w-7) = 0

Now we solve both terms by = 0 seperately:

w + 8 = 0

= -8

w - 7 = 0

w = 7

Solutions:

w = 7, -8

Now that we have our solutions, we can choose which one best fits our scenario. In this case, 7 will fit the best.

To check this, we just plug it all in!

Length: 7 + 1 = 8

Width: 7

Area is length x width. So now we multiply:

8 x 7 = 56.

The width of this rectangle is 7 units.