An object is launched directly in the air at a speed of 96 feet per second from a platform located 12 feet in the air. The motion of the object can be modeled using the function f(t)=−16t2+144t+12, where t is the time in seconds and f(t) is the height of the object. When, in seconds, will the object reach its maximum height? Do not include units in your answer.

to rewrite a literal equation you may need to divide by a number, or by a variable.

hope i .

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x