What is the end behavior of the graph of f(x) = x5 – 8x4 + 16x3? The graph touches, but does not cross, the x–axis at x =
.

The graph of the function crosses the x–axis at x =
.

The graph touches, but does not cross, the x–axis at x = 4

The graph of the function crosses the x–axis at x = 0

Step-by-step explanation:

f(x) = x⁵ – 8x⁴ + 16x³

     =x³ (x² - 8x + 16)

     = x³ (x-4)²

f(x) = 0      x = 0 or x = 4

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!