Pl help fast The quadratic function y = -x2 + 10x - 8 models the height of a trestle on a bridge. The x-axis represents ground level.

To find where the section of the bridge meets ground level, solve 0 = -x2 + 10x - 8.

Where does this section of the bridge meet ground level?

Choose an equation that would be used to solve 0 = -x2 + 10x – 8

(x + 25)2 = –8

(x – 5)2 = 17

(x – 10)2 = 25

The trestle meets ground level at 0.9 units and 9.1 units

Step-by-step explanation:

∵ -x² + 10x - 8 = 0 ⇒ × (-1)

∴ x² - 10x + 8 = 0

∵ 10x/2 = 5x ⇒ (x) × (5) ⇒ square x is x² and square 5 is 25

By using completing square form

∴ (x² - 10x + 25) - 25 + 8 = 0

∴ (x - 5)² - 17 = 0

∴ (x - 5)² = 17 ⇒ take square root for both sides

∴ x - 5 = -√17 ⇒ x = -√17 + 5 = 0.9

∴ x - 5 = √17 ⇒ x = √17 + 5 = 9.1

∴ The trestle meets ground level at x = 0.9 and x = 9.1

I hope it helps you out!

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