Three blue balls numbered 1, 2 and 3 are placed in a bag along withthree red balls also numbered 1, 2 and 3. If two balls are chosen atrandom from the bag, find the probability that the balls: a. are a red 1 and a blue 3
b. are both red.
c. are both red and have a sum of 5.
d. are different colours and have a sum of 6.
e. consist of at least one red.

PLEASE HELP!

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

3x + 4y -25 =0 represents the amount of change sianna should recieve

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step-by-step explanation: