You are given an equation of a line and a point. use substitution to determine whether the point is on the line. y=3x+7; A(2,13

(1,10) That is the slope, if there is another line then the answer will be different!

Step-by-step explanation:

This is the slope-intercept formula, (y=mx+b)

Start by finding the y-intercept which is Positive 7 or plus 7 you should find it on the y-axis on the positive side.

Then you will need to identify the slope, the slope, in this case is 3, which needs to be in rise over run formula so 3 over 1.

To find a slope you must start at the y-intercept in your case is 7, then you must go up 3 and right 1.

Then identify the x and y axis.

If this is not the answer please provide this equation and another one to get them intersecting to get one point.

i dont get it. where are the "descriptions"?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.