Mathematics, 03.09.2021 06:40 jcutler2751
Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term, a and the common ratio, r. I'll mark u as the brainliest, do help me!ββ
Answers: 2
![\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2](/tpl/images/2453/9770/0d8ba.png)
Another question on Mathematics
Mathematics, 20.06.2019 18:04
Given that (x-3) is a factor of f(x)=x^3+ax^2-x-6, find a and hence the number of real roots or the equation f(x)=0
Answers: 3
Mathematics, 21.06.2019 18:30
Can someone check if i did this right since i really want to make sure itβs correct. if you do you so much
Answers: 1
Mathematics, 21.06.2019 20:10
In the diagram, points d and e are marked by drawing arcs of equal size centered at b such that the arcs intersect ba and bc. then, intersecting arcs of equal size are drawn centered at points d and e. point p is located at the intersection of these arcs. based on this construction, m , and m
Answers: 1
You know the right answer?
Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term, a and the common ratio,...
Questions
Social Studies, 18.08.2021 20:50
History, 18.08.2021 20:50
English, 18.08.2021 20:50
Mathematics, 18.08.2021 20:50
English, 18.08.2021 20:50
Physics, 18.08.2021 20:50
Social Studies, 18.08.2021 20:50
Computers and Technology, 18.08.2021 20:50
Mathematics, 18.08.2021 20:50
Mathematics, 18.08.2021 20:50
