If no (A) = 40%, no (B) = 30%, n (A∩B) = 20% then find n (
(A B)
using formula.

solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).

Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,

n(A∪B)=n(A)+n(B)−n(A∩B)

⇒40=20+30−n(A∩B)

⇒40=50−n(A∩B)

⇒n(A∩B)=50−40

⇒n(A∩B)=10

Hence, n(A∩B)=10

Step-by-step explanation:

hope it helps you friend ☺️

n(a) =40

n(b) =30

n(aπb) =20

n(aub)=x (let)

we know that

n(aub)=n(a)+n(b)–n(aπb)

x=40+30–20

x=70-20

x=50

n(aub)=50

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

i have no idea just need points sorry

step-by-step explanation: