when solving |5k+6|=39 what two equations would we set up to allow us to get rid of the absolute value bars?

A

Step-by-step explanation:

In order to get rid of the absolute value bars we would need to put the number outside of the absolute value bars into two signs. One is going to be positive and one is going to be negative. So in this case, the two equations would be 5k+6=39 and 5k+6=-39

what the question so we can you out

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )