If f(x) = 9x10 tan−1x, find f '(x). 90x9tan−1x + 9x10 1 over the quantity 1 plus x squared
90x9tan−1x + 9x10tan−2x
90x9tan−1x − 9x10 1 over the square root of the quantity 1 minus x squared
90x9tan−1x + 9x10 1 over the square root of the quantity 1 minus x squared
those are my choices

f(x) = 9x10tan-1(x)

Use the product rule to derive.

Let g(x) = 9x10

Let h(x) = tan-1(x)

Product rule:

f'(x) = g'(x)h(x) + g(x)h'(x)

f'(x) = 90x9tan-1 - [9x10 / (1 + x2)]

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

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