Write the equation of the line parallel to y=1/3x-6 that passes through the point (-12,3) in slope-intercept form.

y=1/3x+7

Step-by-step explanation:

1. The given equation is y=1/3x-6 and it has to be parallel passing through (-12,3), so you just plug in the x and y values into the equation y=mx+b with 1/3 as the slope since its parallel (meaning the slope is the same for both eqts)

2. 3=1/3(-12)+b

3. 3=-4+b

4. 7=b

5. So, the equation is y=1/3x+7

where are the options?

step-by-step explanation:

a - base

b - exponent

so,