Please explain how you got your answer also, thank you :)

Step-by-step explanation:

1) y=x²-8x+5=0

2) x²-8x=-5

3) x²-8x+16=9

4) (x-4)²=9

5)(x-4)²-9=0

((x-4)-3)((x-4+3)=0

(x-7)(x-1)=0

x=7 or x=1

sol={1;7}

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

(3x-8) or (3x+8)

step-by-step explanation: