If a truck starts from rest and it has acceleration of 4m/s square for 5 second , calculate it's final velocity . What will be the distance travelled by the truck during the time interval​

Answers:

Final Velocity = 20 m/s

Distance Traveled = 50 meters

Explanation:

The truck starts from rest, so its initial starting velocity is 0 m/s. I'll denote this as Vi = 0.

The final velocity is what we want to find, so we want to solve for Vf.

The acceleration is a = 4 m/s^2.

The change in time is t = 5 seconds.

So,

a = (Vf - Vi)/(t)

4 = (Vf - 0)/5

4*5 = Vf

20 = Vf

Vf = 20

The final velocity is 20 m/s.

Now let's calculate the distance traveled using the following kinematics equation:

d = 0.5*(Vi+Vf)*t

d = 0.5*(0+20)*5

d = 0.5*(20)*5

d = 10*5

d = 50

The truck travels a total distance of 50 meters.

This is another way to calculate the distance traveled where we don't need to find Vf

d = Vi*t + 0.5*a*t^2

d = 0*5 + 0.5*4*5^2

d = 0 + 2*25  

d = 50

However, since your teacher wanted you to compute Vf, I think you should stick to the previous set of steps.

answer: it's d

step-by-step explanation:

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft