What is an equation of the line that passes through the point (3,-1)(3,−1) and is parallel to the line 5x+3y=65x+3y=6?

Step-by-step explanation:

5x+3y = 6

5x = 6 - 3y

5x = 3(2-y)

5x/3 = 2 - y

y = 2 - (5x/3)

slope = x coefficient.

= - 5/3

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

new slope = 3/5

the equation formula

y = mx + b

m = new slope = 3/5

y = (3x/5) + b

From the point given (3 , -1 )

x = 3.

y = -1

-1 = (9/5) + b

b =( -5/5) - (9/5)

b = - 14 / 5