Please help only part iv ​

f(3) + f(-3) = 10

Step-by-step explanation:

f(3) = 5 - 2(3)

f(-3) = 5 - 2(-3)

f(3) + f(-3) = 5 - 2(3) + 5 - 2(-3)

f(3) + f(-3) = 5 - 6 + 5 +6

f(3) + f(-3) = -1 + 11

f(3) + f(-3) = 10

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

idk

step-by-step explanation: