Which equation has roots of which equation has roots of 3 + sqrt 2? x^2 - 4x +1=0
А
B.
x^2 – 18 = 0
с
x^2 + 6x+ 7 = 0
D
x^2 - 6x + 7 = 0

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

step-by-step explanation: s

if im not mistaking its

step-by-step explanation:  

4

step-by-step explanation: