One-sixth of the smallest of three consecutive even integers is three less than one-tenth the sum of the
other even integers. Find the integers. this
#49 with work pleasee

The three even, consecutive integers are 72, 74, and 76.

Step-by-step explanation:

Let a be the first even integer.

Then the other two consecutive integers, b and c, will be represented by:

One-sixth of the smallest (that is, a) is three less than one-tenth the sum of the other two even integers (that is, b and c).

Therefore:

Solve for a. Substitute:

Simplify and solve for a:

Hence, the first even integer is 72.

Therefore, the two other consecutive even integers must be 74, and 76.

In conclusion, the three even, consecutive integers are 72, 74, and 76.

i think it might be a but you might want a second opinion

can you put the picture up?

step-by-step explanation: