Two hunters leave the same camp site in the morning, on their four wheelers. One heads 30° north of east for 50 km, and the other goes for 64 km heading 80° west of south, and they stop for a break. Calculate the distance that separates the two hunters (Express your answer to 4 decimal place).

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0