A food inspector examined 16 jars of a certain brand of jam to determine the percent of foreign impurities. The following data were recorded: 2.4 2.3 3.1 2.2 2.3 1.2 1.0 2.4 1.7 1.1 4.2 1.9 1.7 3.6 1.6 2.3 Using the normal approximation to the binomial distribution, perform a sig test at the 0.05 level of signigicance to test the null hypothesi that the median percent of impuritites in this brand of jam is 2.5% against the alternatie that the median percent of ipurities is not 2.5%.

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

what