Mathematics, 18.08.2021 15:50 knevis
I have no idea what I did wrong but my answer came out as 1/2 over 4 ._.
Can someone help a poor soul?
(Algebra 2) (Khan Academy)
Answers: 3
Mathematics, 21.06.2019 12:50
What values of data might affect the statistical measures of spread and center
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Mathematics, 21.06.2019 22:00
If abcde is reflected over the x-axis and then translated 3 units left, what are the new coordinates d? are he re
Answers: 1
Mathematics, 22.06.2019 01:00
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
Answers: 3
Mathematics, 22.06.2019 02:00
4. bob solved the inequality problem below incorrectly. explain his error and redo the problem showing the correct answer. ? 2x + 5 < 17 ? 2x + 5-5 < 17-5 -2x/-2 < 12/-2 x < -6
Answers: 2
I have no idea what I did wrong but my answer came out as 1/2 over 4 ._.
Can someone help a poor s...
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