if the sum p(x)=ax^2-3x+b and q(x)=3x^3-12x^2+cx-13 is r(x)=3x^3-8x^2+3x-5,then find the value of a, b and c.

a=4, b=8, c=6

Step-by-step explanation:

ATQ, p(x) + q(x) = r(x)

3x^3-(12-a)x^2-(3-c)x+b-13 = 3x^3-8x^2+3x-5

Comparing the coefficients, we have

12-a=8, a=4

b-13=-5, b=8

-(3-c)=3, c=6

i could probably can you me with a question of mine?

step-by-step explanation:

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°