If the 6th term of an A. p is 11and its first term is 1 find the common diferent

Step-by-step explanation:

a = 1 (1)

a6 = 11

=> a + 5d = 11 (2)

Substituting (1) in (2)

=> 1 + 5d = 11

=> 5d = 10

=> d = 2

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Step-by-step explanation:

In an AP, Tn = a + (n - 1)d

T6 = a + 5d = 11

The first term = a = 1

∴ T6 = 1 + 5d = 11

5d = 11 - 1

5d = 10

∴ d = 2

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

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