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Mathematics, 16.08.2021 17:30 MayFlowers

H(1) = 9
h(2) = 3
h(n)=h (nβˆ’2) β‹… h(nβˆ’1)
h(3)


H(1) = 9
h(2) = 3
h(n)=h (nβˆ’2) β‹… h(nβˆ’1)
h(3)

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Answers: 1

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You know the right answer?
H(1) = 9
h(2) = 3
h(n)=h (nβˆ’2) β‹… h(nβˆ’1)
h(3)
...
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