Solve for X: 2^3x + 1 = 2^10

please look at photo and give detailed steps!! thank you

Step-by-step explanation:

since the bases are the same all you have to do is just get the powers of both bases which is 3x + 1 and 10

you're then going to equate 3 x + 1 to 10 and then you have to make +1 cross to the other side making it become -1

you then can subtract 1 from 10 leaving you with 9

and at the LHS we have 3x

we are gonna get rid of the three by dividing it into itself and the 9 at the RHS then X = 3

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°