Of the 1,000 students in a local college, 420 own brand x mobile phones and 580 own brand y mobile phones. of these students, 80 own both brands of mobile phones. find the probability that a student chosen at random has a brand x mobile phone given that he has a brand y mobile phone.
2/14
5/21
3/28
4/29

The probability that a student chosen at random has a brand X mobile phone given that he has a brand Y mobile phone is 4/29.

Step-by-step explanation:

Since, the total number of students, n(s) = 1,000

The number of students who have X mobile phones, n(X) = 420,

And, number of students who have Y mobile phones, n(Y) = 580,

Thus, the probability of the student that has Y phones,

While, the number of students who have both phones, n(X∩Y) = 80

Thus, the probability of the student who has both phones,

Hence, the probability that a student chosen at random has a brand X mobile phone given that he has a brand Y mobile phone.

Hence, the required probability is 4/29.

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80