Please help explanation if possible

y = | x-5|

Step-by-step explanation:

y = |x-h| +k  where (h,k) is the center of the "v"

The "v" is located at (5,) so h=5 and k = 0

y = | x-5| +0

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: