1. Determine the set of each of the following equations for 0° ≤ x 360° or 0° ≤ t ≤ 360° a) sin 2 x°= 1/2√2

2. find all the solution in the interval 0° ≤ z ≤ 360° of the following equation
sin 3 z = - 0,42

Please help Me​

a).

since sine is in the 2nd quadrant, other angle = 180° - x:

we must make two rotations since it's a double angle:

divide each angle by 2:

Answer = {x: x = 22.5°, 67.5°, 112.5°, 157.5°, 247.5, 337.5°}

b).

since ans is negative, we take the quadrants of cosine and tangent:

we make three rotations:

answer is {z : z = 128.3°, 171.7°, 231.7°, 291.7°, 351.7°}

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

41*67/2=1373.5

step-by-step explanation:

i just used a calculator