The area of triangle ABC is _.

The formula for the area of a triangle is A = (base · height)/2, but when we look at this problem, there's no base or height!

Looking at the triangle on the right, we can use the Pythagorean Theorem to find the height:

h² + 16² = 20²

h² + 256 = 400

h² = 144

h = ± 12

In this case, the height is 12 because you can't have negatives when you are working with lengths of sides and other things like this in geometry.

So now we've found the height, but we still don't know the full base! So, we can use the height that we just found to use the Pythagorean Theorem for the left triangle!

B² + 12² = 15²

B² + 144 = 225

B² = 81

B = ±9

So once again, our answer is just 9.

But, because the base is CB, we have to add:

b = 9 + 16  

b = 25.

Now we have the base and height, so we can put them into our formula to solve for the area of the triangle:

A = (25 · 12) / 2

A = 300 / 2

A = 150

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .