Quadrilateral ABCD has vertices A(–1, –2), B(–1, 3), C(4, 3) and D(4, –2). It’s dilated by a factor of 2 with the center of dilation at the origin. What are the coordinates of the resulting quadrilateral A’B’C’D

9514 1404 393

Step-by-step explanation:

Dilation about the origin multiplies each coordinate value by the dilation factor.

  A' = 2A = 2(-1, -2) = (-2, -4)

  B' = 2B = 2(-1, 3) = (-2, 6)

 C' = 2C = 2(4, 3) = (8, 6)

  D' = 2D = 2(4, -2) = (8, -4)

c

step-by-step explanation:

at least i think its

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204