The average of A and B is 6. The average of X, Y, and Z is 16. What is the average of A, B, X, Y, and Z?

12

Step-by-step explanation:

Average of A and B is 6

(A+B) /2 = 6

Multiply each side by 2

A+B = 12

average of X, Y, and Z is 16

(X+Y+Z)/3 = 16

Multiply each side by 3

(X+Y+Z) = 48

To find the average of all of them

(A+B+X+Y+Z)/5

replace A+B with 12 and X+Y+Z with 48

(12+48)/5

60/5 = 12

i believe that the answer is

b. y-1=-2(x-4)

hope this !