Help please! thanks!
Find the length of AB
A. 2.89
B. 33.13
C. 378.63
D. 377.19

Explanation:

Segment AB is already given to be 19 miles long.

I'm assuming your teacher meant to ask about side BC, which is side 'a' since it's opposite angle A.

Use the law of cosines to find the missing side

a^2 = b^2 + c^2 - 2*b*c*cos(A)

a^2 = 12^2 + 19^2 - 2*12*19*cos(138)

a^2 = 843.874040417691

a = sqrt(843.874040417691)

a = 29.0495101579647

a = 29 when rounding to the nearest whole number

Side BC is roughly 29 miles long.

dude   i don't even know. i've been trying for hours.

step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source: