A pendulum is swinging next to a wall. The distance D(t)D(t)D, left parenthesis, t, right parenthesis (in \text{cm}cmstart text, c, m, end text) between the bob of the pendulum and the wall as a function of time ttt (in seconds) can be modeled by a sinusoidal expression of the form a\cdot\sin(b\cdot t)+da⋅sin(b⋅t)+da, dot, sine, left parenthesis, b, dot, t, right parenthesis, plus, d. At t=0t=0t, equals, 0, when the pendulum is exactly in the middle of its swing, the bob is 5\text{ cm}5 cm5, start text, space, c, m, end text away from the wall. The bob reaches the closest point to the wall, which is 3\text{ cm}3 cm3, start text, space, c, m, end text from the wall, 111 second later. Find D(t)D(t)D, left parenthesis, t, right parenthesis. \textit{t}tstart text, t, end text should be in radians.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12