the graph of the parabola y=3(x+5)2-2 has vertex (-5,-2). if this parabola is shifted 1 unit down and 6 units to the right, what is the equation of the new parabola?​

y = 3(x-1)^2 -3

Step-by-step explanation:

y = 3(x+5)^2 - 2

vertex: (-5, -2)

1 unit down :

-2 - 1 = -3

6 units to the right:

3(x+5-6)^2 -2

3(x-1)^2 - 2

make what's in the parenthesis equal to 0:

(x-1)^2 = 0

x = 1

or

-5 + 6 = 1

new vertex : (1, -3)

equation : y = 3(x-1)^2 -3

answer: x=60